Given:
m1=0.506kg
u1=3.76m/s
m2=0.253kg
u2=0
Find=v1
Solution:
After collision masses travels with velocity v1 and v2
Conserving Momentum
m1u1+m2u2=m1v1+m2v2................... (i)
by Conservation of Energy
1/2.m1u1²₊1/2.m2u2²=1/2.m1v1²₊1/2.m2v2²....................(ii)
After simplifying both (i) and (ii) equation
v1=(m1-m2/m1₊m2)u1
v2=(2m1/m1₊m2)u1
v1=((0.506-0.253)/(0.506+0.253))x3.76 m/s
v1=1.253 m/s
Law of Conservation of Energy
The law of conservation of energy states that energy is neither created nor destroyed, and can only be converted from one form of energy to another.
Conservation of momentum
Conservation of momentum states that within a problem region, the amount of momentum remains constant.
To learn more about Conservation of momentum concept, Visit this link
https://brainly.com/question/14604866
#SPJ4
