The number of units x that produces a maximum revenue with the expression given is x = 0.
To find the value of x that maximizes the revenue function R, we can take the derivative of R with respect to x and set it equal to 0. This will give us the critical point of the function.
The derivative of the function R with respect to x is:
R'(x) = 342x - 0.18x²
Setting this equal to 0, we get:
342x - 0.18x² = 0
Solving for x, we find that x = 0 or x = 1900.
However, we need to consider the constraints of the problem to determine which value of x is the optimal solution. If x is a number of units, then x cannot be negative. Therefore, the only valid solution is x = 0.
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