Respuesta :
The limiting reactant is [tex] C_{7}[/tex][tex] H_{16}[/tex].
[tex] C_{7}[/tex][tex] H_{16}[/tex] + 11[tex] O_{2}[/tex] -> 7[tex] CO_{2}[/tex] + 8[tex] H_{2}[/tex]O
Available number of moles of [tex] C_{7}[/tex][tex] H_{16}[/tex] = mass ÷ molar mass
Available number of moles of [tex] C_{7}[/tex][tex] H_{16}[/tex] = 125 ÷ 100
Available number of moles of [tex] C_{7}[/tex][tex] H_{16}[/tex] = 1.25 moles
Available number of moles of [tex] O_{2}[/tex] = 375 ÷ 32
Available number of moles of [tex] O_{2}[/tex] = 11.7 moles
So, the number of moles of [tex] O_{2}[/tex] required = number of moles of [tex] C_{7}[/tex][tex] H_{16}[/tex] × 11
Number of moles of [tex] O_{2}[/tex] required = 1.25 × 11
Number of moles of [tex] O_{2}[/tex] required = 13.75 moles
Number of moles of [tex] C_{7}[/tex][tex] H_{16}[/tex] required = 11.7 ÷ 11
Number of moles of [tex] C_{7}[/tex][tex] H_{16}[/tex] required = 1.06 moles
As the number of moles of [tex] C_{7}[/tex][tex] H_{16}[/tex] are less than the required, it is the limiting reactant.
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