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Zirconium has 5 stable isotopes as shown below. Determine the % abundance of zr-92: isotope mass (amu) % abundance zr-90 89.905 51.45 zr-91 90.906 ?? Zr-92 91.905 ?? Zr-94 93.906 17.38 zr-96 95.908 2.80

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Answer is: the % abundance of Zr-92 is 17.15%.

Ar(Zr) = ω(Zr-90) · Ar(Zr-90) + ω(Zr-91) ·Ar(Zr-91) + ω(Zr-92) ·Ar(Zr-92) + ω(Zr-94) ·Ar(Zr-94) + ω(Zr-96) ·Ar(Zr-96).

91.224 = 89.905 · 0.5145 + 90.906 · 0.1122 + 91.905 · ω(Zr-92) + 93.906 · 0.1738 + 95.908 · 0.0280.

91.905 · ω(Zr-92) = 91.224 - (46.256 + 10.199 + 16.320 + 2.685).

ω(Zr-92) = 15.764 ÷ 91.905.

ω(Zr-92) = 0.1715 · 100% = 17.15%.

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