Molar Mass of K2SO4
K= 39*2= 78 amu
S= 32*1 = 32 amu
O=16*4 = 64 amu
--------------------------
Molar Mass of K2SO4 = 78 + 32 + 64 = 174 g/mol
Data:
W (Molality) = ?
m1 (mass of the solute) = 12.50 g
m2 (mass of the solvent) = 100.00 g (solution) - 12.50 g (solute) = 87.50 g (Solvent)
MM (molar mass) = 174 g/mol
Formula:
[tex]W = \frac{1000* m_{1} }{ m_{2}*MM } [/tex]
Solving:
[tex]W = \frac{1000* m_{1} }{ m_{2}*MM } [/tex]
[tex]W = \frac{1000*12.50 }{87.50*174 }[/tex]
[tex]W = \frac{12500}{15225} [/tex]
[tex]\boxed{\boxed{W \approx 0.821 molal}}[/tex]
