Respuesta :
The correct answer is:
[tex] A(r(t))=\pi(0.25+2t+4t^2) [/tex]
Explanation:
To write a composite function, we apply one function to another given function. In this case, we want to find area in terms of time; this means that the function A(r) gets applied to the function r(t).
In order to do this, we replace r with r(t). We already know that r(t)=0.5+2t; this means we replace r with 0.5+2t:
A(r(t))=π(0.5+2t)²
To simplify this, we simplify the squared term:
A(r(t)) = π(0.5+2t)(0.5+2t)
A(r(t)) = π(0.5*0.5+0.5*2t+2t*0.5+2t*2t)
A(r(t)) = π(0.25+t+t+4t²)
A(r(t)) = π(0.25+2t+4t²)
The composite function to find the area of the region at time t is[tex]A(r(t))=\pi (0.25+2t+4t^2)[/tex].
Given information:
The radius is given by the function [tex]r(t)=0.5+2t[/tex]. Here, t is time in hours.
As we know that, the area of circular region (circle) is given by the formula [tex]A(r)=\pi r^2[/tex].
Now, to get a composite function, replace the value of [tex]r[/tex] in area expression, as:
[tex]A(r(t))=\pi.(0.5+2t))0.5+2t)\\\\A(r(t))=\pi(0.5\times 0.5+0.5\times 2t\times 2t.0.5+2t\times 2t)\\\\A(r(t))=\pi \times (0.25+2t+4t^2)[/tex]
Therefore, the function can not be simplified any further. Hence, the required function to find the area of the region at time t will be:
[tex]A(r(t))=\pi (0.25+2t+4t^2)[/tex].
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