Answer:
x = -1.8 two equations approximately equal.
Step-by-step explanation:
Given : y = [tex]\frac{1}{(x+2)}[/tex] ,y =[tex]y = x^{2} +2[/tex]
To find : which x-value are the two equations approximately equal.
Solution : We have given that
y = [tex]\frac{1}{(x+2)}[/tex] -----( equation 1)
[tex]y = x^{2} +2[/tex]------( equation 2).
Plug the of equation 2 in 1
[tex]x^{2} +2[/tex] = [tex]\frac{1}{(x+2)}[/tex].
[tex]x^{2}(x+2) +2(x+2)[/tex] = 1.
x³+2x² +2x+4 = 1
On subtracting 1 both sides.
x³+2x² +2x+3 = 0
For x = -1.8
Therefore, x = -1.8 two equations approximately equal.
