Respuesta :
Deer Lake - Summerville - Cypress - Liberty
Deer Lake to Summerville is 3
Summerville to Cypress is 1
Cypress to Liberty is 2
So if the entire trip is 360 miles, then you will take 3+1+2=6.
So from Deer Lake to Cypress, it would be 3+1=4.
So 4/6.
360÷6=60
Therefore 60×4=
240 Miles from Deer Lake to Cypress!
Deer Lake to Summerville is 3
Summerville to Cypress is 1
Cypress to Liberty is 2
So if the entire trip is 360 miles, then you will take 3+1+2=6.
So from Deer Lake to Cypress, it would be 3+1=4.
So 4/6.
360÷6=60
Therefore 60×4=
240 Miles from Deer Lake to Cypress!
Answer:
The ride from Deer Lake to Cypress is 240 [mi]. To find the solution we use the segment addition postulate
Explanation:
The segment addition postulate states that for a line with initial point A and finish point C, a third point B lies in the segment only if the distances between points satisfies the following equation:
- AB + BC = AC
In this case, we have a line with four points:
A - Deer Lake
B - Summerville
C - Cypress
D - Liberty
And we are required to find the distance from Deer Lake to Cypress (AC) knowing that AD = 360 [mi] and knowing that:
- AD = AB + BC + CD --> This is the equation derived from the segment addition postulate.
- AB = 3BC --> Going from Deer Lake to Summerville takes three times as long than going from Summerville to Cypress. Since the speed is constant, three times the time means three times the distance.
- CD = 2BC --> (Same expalantion as above, except for different locations)
We end up with 3 equations and 3 unknowns. All we need to do now is to solve it
- Substitue equation 2 and 3 in equation 1 and solve for BC
- Use equation 2 to get AB
- Use equation 3 to get BC
They want us to find AC (Deer Lake to Cypress), we knoe the postulate, we know the values:
- AC = AB + BC = 180 + 60
- AC = 240 [mi]
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