Respuesta :
Answer:
a) 7.48 meter is the parameter for the path the ladybug flies between the points, including domain.
b) 1.87 meter distance does the ladybug travel per second
Step-by-step explanation:
This is problem from coordinate geometry and we can crack it by few steps .
First of all , the required formula to solve it is ,
l = √ ( x₁ - x₂ )² + ( y₁ - y₂ )² + ( z₁ - z₂)²
where , x₁ , y₁ , z₁ is the coordinate of first point and x₂ , y₂ , z₂ is the coordinate of second point and l is the distance between two point .
Here x₁ = 2 , y₁ = 7 , z₁ = 1
and x₂ = 4 , y₂ = 1 , z₂ = 5
Now we have to put values in the formula ,
l = √ ( 2 - 4 )² + ( 1 - 7 )² + ( 5 - 1 )²
l = √ 2² + 6² + 4²
l = √ 4 + 36 + 16
l = √ 56 = 7.48 meter
So, the ladybug flies 7.48 meter while traveling point one to point two .
Speed taken to fly along this path is , l/t = S , where S is denoted as speed .
S = 7.48 / 4 = 1.87 meter/ second
To know more about coordinate geometry ,
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