Respuesta :
The capacitance of capacitor is 6.44 μF.
We need to know about the capacitance of the air-filled capacitor to solve this problem. The capacitance of the air-filled capacitor depends on the charge and voltage. It can be written as
C = Q/V
where C is capacitance, Q is charge and V is voltage.
Capacitance also can be calculated by the area and distance between the capacitor plate
C = εo . A / d
where εo is vacuum permittivity (8.85 x 10¯¹² F/m), A is the area of the plate and d is distance.
From the question above, we know that
A = 0.8 m²
d = 1.1 x 10¯⁶ m
By substituting the given parameters, we can calculate the capacitance
C = εo . A / d
C = 8.85 x 10¯¹² . 0.8 / 1.1 x 10¯⁶
C = 6.44 x 10¯⁶ F
C = 6.44 μF
Hence, the capacitance of capacitor is 6.44 μF.
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