Write a slope-intercept equation for a line passing through the given point that is parallel to the given line. Then write a second
equation for a line passing through the given point that is perpendicular to the given line.
(-7, 0), y=-0.9x + 4.4

Respuesta :

The equation of the line parallel and perpendicular are y = -0.9(x+7) and y = 10/9(x+7) respectively

Equation of a line

The equation of a line in point slope form is expressed as;

y - y₁ =m(x-x₁) (Parallel)

y - y₁ =-1/m(x-x₁)  (Perpendicular)

Given the following

Point = (-7, 0)

Slope = -0.9

Substitute

y -0 = -0.9(x-(-7))

y = -0.9(x+7)

Similarly for the perpendicular line

y -0 = -1/-0.9(x-(-7))

y = 10/9(x+7)

Hence the equation of the line parallel and perpendicular are y = -0.9(x+7) and y = 10/9(x+7) respectively

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