The cost for using 40 HCF of water is $67.72
To solve this question, we use the following representations
Using the above representations, we have the following points
(x, y) = (14, 32.62), (48, 78.52)
For 40 HCF of water, we have
(x, y) = (40, y)
The slope of a linear equation is calculated using
m = (y2 - y1)/(x2 - x1)
So, we have
m = (78.52 - 32.62)/(48 - 14) = 1.35
m = (78.52 - y)/(48 - 40)
Substitute m = 1.35 in m = (78.52 - y)/(48 - 40)
So, we have:
1.35 = (78.52 - y)/(48 - 40)
Evaluate the difference
1.35 = (78.52 - y)/8
Multiply both sides by 8
10.8 = 78.52 - y
This gives
y = 78.52 - 10.8
Evaluate the difference
y = 67.72
Hence, the cost for using 40 HCF of water is $67.72
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