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Casey buys sandwiches and bags of chips. Each sandwhich cost three times as much as a bag of chips.bshe bought 5 sandwiches for $6 each and spent $42. How many bags b did she buy?

Respuesta :

adioabiola

Therefore, the number of bags of chips Casey buys if each sandwhich cost three times as much as a bag of chips is 6 bags of chips.

Equation

  • Cost of each bag of chips = y

Cost of sandwiches = 3y = $6

3y = $6

y = $6/2

y = $3

  • Number of sandwiches bought = 5

  • Number of bags of chips = x

  • Total spent = $42

Total spent = (Cost of each bag of chips × Number of bags of chips) + (Cost of sandwiches × Number of sandwiches bought)

42 = (y × x) + ($6 × 5)

42 = (2 × x) + 30

42 = 2x + 30

42 - 30 = 2x

12 = 2x

x = 12/2

x = 6 bags of chips

Therefore, the number of bags of chips Casey buys if each sandwhich cost three times as much as a bag of chips is 6 bags of chips

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