The length of Line GH of the given Line segment is gotten as; 105
From the figure:
AD = DC = 56
Thus;
56 = AE + ED (because E is the mid point of AD)
Thus;
ED = AE = 56/2
ED = AE = 28
AE = 28 = EF + FD (F is the mid point of ED)
EF = FD = 28/2
EF = FD = 14
EF = 14 = EG + GF (Because G is the mid point of EF)
EG = GF = 14/2
EG = GF = 7
AC = DC + AD (D is the mid point of AC)
AC = 56 + 56 = 112
AC = BC (C is the mid point of AB)
BC = CH + HB
So, AC = CH + HB (AC = BC)
BD = DH + BH (H is the mid point of BD)
DH = CH + DC (from the figure)
AC = CH + CH + DC
112 = 2CH + 56
CH = 28
GH = GF + FD + DC + CH
GH = 7 + 14 + 56 + 28 = 105
Read more about Division of Line Segments at; https://brainly.com/question/4747771
#SPJ1