We are exponential equation in form [tex]y=AB^x[/tex].
We need to find the values of A and B.
We are given points (10,4), (12,20), (12,35), and (16,300).
Let us check equation in option y=0.003(2.04)^x by plugging those given points in that equation.
Plugging x=10
y=0.003(2.04)^10 = 3.74475.
Plugging x= 12.
y=0.003(2.04)^12 = 15.58416
Plugging x=16.
y= 0.003(2.04)^16 = 269.9.
Now, if we check option B y=2.04(0.003)^x, we have decay factor there 0.003.
So, it would be a decay function.
If we check y=11.27(1.00)^x we have 1.00 so it's not growing exponentially.
And 1.00(11.27)^x is growing at extremely high rate.
Therefore, correct option would be A. y=0.003(2.04)^x.
