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Answer ?
An airplane is waiting to take off on the runway
at the airport. The plane is then cleared for take
off and accelerates down the runway for 26.1 s
to reach a 71 m/s lift off velocity. What was the
airplane's acceleration on the runway? Show all
your work.

Respuesta :

EP0NA

Answer:

2.75 m/s^2

Explanation:

The airplane's acceleration on the runway was 2.75 m/s^2

We can find the acceleration by using the equation: a = (v-u)/t

where a is acceleration, v is final velocity, u is initial velocity, and t is time.

In this case, v is 71 m/s, u is 0 m/s, and t is 26.1 s Therefore: a = (71-0)/26.1

a = 2.75 m/s^2

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