The required length of GH is 7.7.
Given, HJ = 10
m∠J = 40°
These are the equation which contains trigonometric operators such as sin, cos.. etc.. In algebraic operation.
Let assume that there is right angle triangle GHJ.
Where HJ is base and GH is perpendicular.
Now,
cos40 = GH/HJ
GH = cos40 HJ
GH = 10 cos40
GH = 7.7
Thus, the required length of GH is 7.7.
Learn more about trigonometry equations here:
brainly.com/question/22624805
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