The compound HgO can be decomposed to form Hg and O2. This can be represented at the atomic level by a chemical equation:
2HgO 2Hg + O2

According to the law of conservation of mass, if 23.5 grams of HgO decomposes and 21.8 grams of Hg is formed, how many grams of O2 must simultaneously be formed?

A mole is defined as 6.02214076 × 1[tex]0^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

[tex]2HgO[/tex]→ [tex]2Hg + O_2[/tex]

According to the laws of conservation mass of reactants should be equal to the mass of products.

23.5 grams - 21.8 grams

1.7 grams of [tex]O_2[/tex] will be formed.

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The compound HgO can be decomposed to form Hg and O2. This can be represented at the atomic level by a chemical equation: 2HgO 2Hg + O2 According to the law of conservation of mass, if 23.5 grams of HgO decomposes and 21.8 grams of Hg is formed, how many grams of O2 must simultaneously be formed?

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The compound HgO can be decomposed to form Hg and O2. This can be represented at the atomic level by a chemical equation:
2HgO 2Hg + O2

According to the law of conservation of mass, if 23.5 grams of HgO decomposes and 21.8 grams of Hg is formed, how many grams of O2 must simultaneously be formed?