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What is the freezing point, in °C, of
a 0.655 m solution of C4H10 in
benzene?
FP (benzene) = 5.5 °C
Kr(benzene) = 5.12°C/m
[?] °C
Give your answer to the thousandths place.
Freezing Point
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Respuesta :

pstnonsonjoku

The freezing point of the solution is - 2.15.

What is the freezing point?

The freezing point is the point at which a liquid is changed to solid. We can use the formula;

ΔT = K m I

ΔT = temperature change

K = freezing constant of benzene

m = molality

i = Van't Hoff factor

Now;

ΔT =  5.12°C/m * 0.655 m  * 1

ΔT = 3.35°C

ΔT = Freezing point of pure benzene - Freezing point of solution  

Freezing point of solution  = ΔT -  Freezing point of pure benzene

= 3.35°C -  5.5 °C = - 2.15

Learn more about freezing point:https://brainly.com/question/3121416

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