HELP ASAP!!!

When the polynomial 2x^3 + mx^2 + nx – 2 is divided by x – 3, the remainder is 4. When
divided by x – 2, the remainder is 2. What are the values of m and n?

Respuesta :

The values of m and n are -29/3 and 40/3 respectively

Factor and remainder theorem

A polynomial is a function that has a leading degree of 2 and greater. Given the polynomial

P(x) = 2x^3 + mx^2 + nx – 2

If  it is divided by x – 3, the remainder is 4 and divided by x – 2, the remainder is 2, hence;

4 = 2(3)^3 + 9m + 3n - 2

4 = 54 + 9m + 3n - 3

9m + 3n = -47

Similarly

2 = 2(2)^3 + 4m + 2n - 2

4m + 2n = -12

Solve simultaneously

9m + 3n = -47 * 2

4m + 2n = -12  * 3

______________
18m + 6n = -94

12m + 6n = -36

Subtract

6m = -58

m = -58/6 = -29/3

For the value of n

4m + 2n = -12

2m + n = -6

2(-29/3) + n = -6

n = -6 + 58/3

n = 40/3

Hence the values of m and n are -29/3 and 40/3 respectively

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