The age of undergraduate students at the U of A has a mean (µ) of 20.66 and a population standard deviation (s) of 2.4. What percentage of students are 21 or older and thus old enough to legally order alcohol at Griff's?

Respuesta :

Using the normal distribution, it is found that 44.43% of students are 21 or older and thus old enough to legally order alcohol at Griff's.

Normal Probability Distribution

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

[tex]\mu = 20.66, \sigma = 2.4[/tex]

The proportion of students that are 21 or older is one subtracted by the p-value of Z when X = 21, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{21 - 20.66}{2.4}[/tex]

Z = 0.14

Z = 0.14 has a p-value of 0.5557.

1 - 0.5557 = 0.4443 = 44.43% of students are 21 or older and thus old enough to legally order alcohol at Griff's.

More can be learned about the normal distribution at https://brainly.com/question/4079902

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