HURRY I NEED HELP 80p
Select the correct answer from each drop-down menu. A cube shaped box has a side length of 15 inches and contains 27 identical cube shaped blocks. What is the surface area of all 27 blocks compared to the surface area of the box? The side length of the blocks is (3,4 or 5) inches, so the total surface area of the 27 blocks is (150, 4,050 or 1350) square inches. This is (5 times, 3 times, one third or one-fifth) the surface area of the box.

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Respuesta :

Answer:

The side length of the blocks is 5 inches.

The total surface area of the 27 blocks is 4050 square inches.

This is 3 times the surface area of the box.

Step-by-step explanation:

Surface area of a cube

SA = 6s²  (where s is the side length)

Given the side length of the box is 15 inches:

SA of box = 6 · 15² = 1350 in²

Surface Area of blocks with 3 inch side lengths:

⇒ SA = 6 · 3² = 54 in²

⇒ SA of 27 blocks = 27 · 54 = 1458 in²

Surface Area of blocks with 4 inch side lengths:

⇒ SA = 6 · 4² = 96 in²

⇒ SA of 27 blocks = 27 · 96 = 2592 in²

Surface Area of blocks with 5 inch side lengths:

⇒ SA = 6 · 5² = 150 in²

⇒ SA of 27 blocks = 27 · 150 = 4050 in²

Therefore, from the given answer options for the total surface area of the 27 blocks, the side length of the blocks must be 5 inches.

To calculate how many times the total surface area of the 27 blocks is to the surface area of the box:

[tex]\implies \dfrac{\textsf{SA of 27 blocks}}{\textsf{SA of box}}=\sf \dfrac{4050}{1350}=3[/tex]

Summary

The side length of the blocks is 5 inches.

The total surface area of the 27 blocks is 4050 square inches.

This is 3 times the surface area of the box.