A card player selects 2 cards from a deck of 52 cards at random without replacement. The deck contains 4 aces.

What is the probability that both cards the player selects are aces?

Respuesta :

Answer:

2/52

Step-by-step explanation:

If he took one ace out of 52 cards then it would have been 4/52

but as he's taking 2 aces out of 52 cards it is 2/52

Answer:

[tex]P(AA) =\frac{1}{221}[/tex]

Step-by-step explanation:

Deck contains = 52 cards

Deck contains = 4 Aces

Probability of choosing ace first time

                                                        [tex]= \frac{4}{52}[/tex]

Probability of choosing ace again without replacement

                                                                                 [tex]=\frac{3}{51}[/tex]

Probability of 2 aces without replacement

                                                               [tex]=\frac{4}{52} \times \frac{3}{51}\\\\=\frac{1}{13} \times \frac{1}{17}\\\\=\frac{1}{221}[/tex]