Given the heat of fusion of water is 6.02 kJ/mol, it takes 12.9 kJ of heat to melt 38.6 g of ice at 0 °C.
Fusion, commonly known as melting, is a physical process in which matter passes from the solid to the liquid state.
We have ice with a mass of 38.6 g at 0 °C. First, we will convert mass to moles using the molar mass of water.
38.6 g × (1 mol/18.02 g) = 2.14 mol
The heat of fusion (ΔH°fus) for water is 6.02 kJ/mol. The heat (Q) required to melt 2.14 moles of ice is:
Q = 6.02 kJ/mol × 2.14 mol = 12.9 kJ
Given the heat of fusion of water is 6.02 kJ/mol, it takes 12.9 kJ of heat to melt 38.6 g of ice at 0 °C.
Learn more about fusion here: https://brainly.com/question/40140
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