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Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options.

x < 5
–6x – 5 < 10 – x
–6x + 15 < 10 – 5x
A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.
A number line from negative 3 to 3 in increments of 1. An open circle is at negative 5 and a bold line starts at negative 5 and is pointing to the left.

Respuesta :

Option 3 and 4. The two options that shows the correct representation of the inequality are:

  • - 6x + 15 < 10 - 5x
  • An open circle is at 5 and a bold line starts at 5 and is pointing to the right

How to solve the inequality

–3(2x – 5) < 5(2 – x)

We have to open up the brackets by multiplying the sides

= -6x + 15 < 10 - 5x

Hence the  third option is certified to be correct.

Next this inequality has to be shown on a number line.

To do this we have to solve the inequality completely

From -6x + 15 < 10 - 5x

we have to take like terms

-6x+5x < 10 - 15

-x < -5

x<5

The sign of inequality has to be reversed given that the coefficient of x was negative.

Hence x>5. The number line would start from the right and it would move towards the right

From the solution here, we can see that the two correct options are

  1. –6x + 15 < 10 – 5x
  2. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.

Read more on number lines here:

https://brainly.com/question/4727909

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