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A 66.0 kg diver is 3.10 m above the water, falling at speed of 6.10 m/s. Calculate her kinetic energy as she hits the water. (Neglect air friction)

Respuesta :

Kinetic energy as she hits the water is 3300 joule.

To find the answer, we need to know about the Newton's equation of motion.

What's the Newton's equation of motion to determine the final velocity?

  • The final velocity is determined as

V²=U²+2aS

  • V= final velocity, U= initial velocity, a= acceleration and S= distance

What's the final velocity of the driver falling from 3.10m with initial velocity of 6.10m/s?

  • Here, a= 9.8m/s², U= 6.10m/s and S= 3.10m
  • So, V²= 6.1²+2×9.8×3.10= 98
  • V= √98= 10m/s

What's the kinetic energy of the driver when touches the water?

Kinetic energy= 1/2×mass×velocity²

= 1/2 × 66 × 10²

= 3300J

Thus, we can conclude that the kinetic energy of the driver is 3300 Joule.

Learn more about the kinetic energy here:

brainly.com/question/25959744

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