Magnitude of electric force = 15 x 10⁻¹⁰ N
Magnitude of weight force = 64.092 x 10⁻⁶ N
Given
Diameter of rain drop = 2.5mm
Radius = 1.25 mm = 1.25 × 10⁻³ m/sec
Drop has a charge = +15pC
15pC = 15×10⁻¹²C
Electric field (E) = 100 N/C
Electric force on the charge
= charge x electric field = qE
= 15 x 10⁻¹² x 100
= 15 x 10⁻¹⁰ N.
This force will act in upward direction as the force on the positive charge will always acts in the direction of the electric field.
Volume of rain droplet(V) = 4/3 π R³
Volume V = 4/3 x 3.14 x ( 1.25 x 10⁻³)³
= 6.54 × 10⁻⁹m³
As Density of water = 1000 kg / m³
Density =Mass/Volume
So, Mass of rain droplet = 1000 x 6.54 x 10⁻⁹ kg
= 6.54 x 10⁻⁶ kg .
Now, Weight(W) = mg
= 6.54 x 10⁻⁶ x 9.8
= 64.092 x 10⁻⁶ N.
As the electric force is 15 × 10⁻¹⁰ N
So, weight force is more than the electric force.
Hence, the magnitude of the electric force on the droplet is less as compare to the weight force.
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