Answer:
Step-by-step explanation:
Arithmetic sequence:
a = first term = 4
d = common difference = second term - first term
= 9 - 4
d = 5
[tex]\sf t_n =a +(n -1)*d[/tex]
= 4 + (n - 1) *5
= 4 + 5n - 5
= 5n -1
Check; n= 1 , first term = 5*1 - 1 = 5 - 1 = 4
n = 2, second term = 5*2 - 1 = 10 -1 = 9
n = 3, third term = 5*3 - 1 = 15 - 1 = 1
The next term, fifth term = 5*5 - 1
= 25 - 1
= 24
