A pile of newspapers in Ms. McGrath’s art class was 17 3/4 inches high. Each consecutive week, for the next 5 weeks, the height of the pile of newspapers increased by 8 7/12 inches. What was the height, in inches, of the pile after 3 weeks?

If you would like to know what was the height, in inches, of the pile after 3 weeks, you can calculate this using the following steps:

17 3/4 inches + 3 * 8 7/12 inches = 71/4 + 3 * 103/12 = 213/12 + 309/12 = 522/12 = 87/2 = 43 1/2 inches

The correct result would be 43 1/2 inches.

Answer Link

calculista calculista · Answer 2 · 2018-09-06T16:43:57+02:00

Let

x--------> the number of weeks

y--------> the height of a pile of newspapers in inches

we know that

[tex]17\frac{3}{4}=\frac{17*4+3}{4} =\frac{71}{4}[/tex]

[tex]8\frac{7}{12}=\frac{8*12+7}{12} =\frac{103}{12}[/tex]

[tex] y=\frac{103}{12}x+\frac{71}{4} [/tex]

To find the height after [tex] 3 [/tex] weeks

Let

[tex] x=3\ weeks[/tex] and substitute in the equation

[tex] y=\frac{103}{12}*3+\frac{71}{4} [/tex]

[tex] y=\frac{174}{4} [/tex]

[tex] y=43.5\ in [/tex]

[tex] y=43\frac{1}{2} \ in [/tex]

therefore

the answer is

the height, in inches, of the pile after [tex] 3 [/tex] weeks is [tex] 43\frac{1}{2} \ in [/tex]