PLEASE HELP ASAP!!!!!!!!!!!!!!!!!!!!!!
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Hello and Good Morning/Afternoon
Let's take this problem step-by-step:
To find the solution to a system of equation
⇒ must set the equations equal to each other
⇒ and solve
Let's put that into action
[tex]x^2-2x+3 = -2x + 12\\x^2-2x+2x+3-12=0\\x^2-9=0\\(x+3)(x-3)=0[/tex]
⇒ either 'x+3' or 'x-3' equals zero
⇒ must find 'x' that satisify either equation
[tex]x-3=0\\x=3\\\\x+3=0\\x=-3[/tex]
Let's find the corresponding f(x) to each x-value
[tex]f(3) = -2(3)+12=-6+12 = 6\\\\f(-3) = -2(-3) + 12=6+12=18[/tex]
Therefore the solutions are (3,6) and (-3,18)
Answer: (3,6), (-3,18)
Hope that helps!
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