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The box survived the fall and is returned to the top of the building. More objects are put into the box, and the box with its contents now has a total mass of 93 kg. The box is dropped, and it reaches a higher terminal speed than before. After reaching terminal speed, what is the magnitude of the air resistance force acting upward on the falling box? (The fact that the heavier object reaches a higher terminal speed shows that the air resistance force increases with increasing speed.)

Respuesta :

911.4N is the air resistance force acting upward on the falling box.

The constant or the highest speed that an object reaches when it falls through a liquid or gas is referred to as terminal velocity.

At terminal velocity,

The Upward force acting on an object(F) = Weight of the falling object(W).

Due to the fact that the two forces are acting in opposing directions, there is no net force acting on the item, and that's why the speed of the object becomes constant.

The Formula used to calculate the Upward force

F = mg...….. Equation(1)

where,

m = total mass of the box

g = acceleration due to gravity = 9.8 [tex]m/s^{2}[/tex]

F = Air resistance force acting upward on the box

Given:

The box with its contents now has total mass of 93Kg

m = 93 kg

g = 9.8 m/s²

Substitute the values into equation (1)

F = 93×(9.8)

F = 911.4 N

Hence, the magnitude of the air resistance force acting upward on the falling box is 911.4N

Learn more about Terminal velocity here https://brainly.com/question/13570045

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