(PLSS HELPP!!) A barge is being towed by two tugboats, using ropes with force vectors as shown.

two vectors named F sub 1 and F sub 2 that share an initial point from the barge each pointing to a different tugboat

Given vector F sub 1 equals open angled bracket 10000 comma 6000 close angled bracket and vector F sub 2 equals open angled bracket 13500 comma negative 7000 close angled bracket comma what is the angle between the ropes?

21°
27°
58°
66°

Respuesta :

The angle between the ropes is 58 degree , Option C is the right answer.

What is a Vector ?

Vector is an object that has both magnitude and direction.

It is given in the question that

[tex]\rm F_1 = 10000i +6000j\\F_2 = 13500 i -7000j\\[/tex]

The angle between the ropes can be calculated as

[tex]\overrightarrow F_1 * \overrightarrow F_2 = |F_1| *|F_2| cos \theta[/tex]

[tex]\rm F_1 = \sqrt{10000^2 + 6000^2}\\\\F_2 = \sqrt{ 13500^2 + 7000^2}[/tex]

[tex]\rm F_1\\[/tex] = 11662

[tex]\rm F_2[/tex] = 15207

[tex]\overrightarrow F_1 * \overrightarrow F_2 = (11662 * 15207)\; cos \theta[/tex]

[tex]\overrightarrow F_1 * \overrightarrow F_2[/tex] = 93000000

93000000 = 11662 * 15207 cos [tex]\rm \theta[/tex]

cos [tex]\rm \theta[/tex] =0.524

[tex]\rm \theta[/tex] = 58.37 degree

The angle between the ropes is 58 degree , Option C is the right answer.

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