Examplelt: A wall of length 10 m was to be built across an open ground. The height of the wall is 4 m and thickness of the wall is 24 cm. If this wall is to be built up with bricks whose dimensions are 24 cm x 12 cm x 8 cm, how many bricks would be required?

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Аноним Аноним · Answer 1 · 2022-03-12T13:39:49+01:00

Answer :

Explanation :

Since the wall with all its bricks makes up the space occupied by it, we need to find the volume of the wall, which is nothing but a cuboid.

Here,

[tex]{\qquad \dashrightarrow{ \sf{Length=10 \: m=1000 \: cm}}}[/tex]

[tex]\qquad \dashrightarrow{ \sf{Thickness=24 \: cm}}[/tex]

[tex]\qquad \dashrightarrow{ \sf{Height=4 m=400 \: cm}}[/tex]

Therefore,

[tex]{\qquad \dashrightarrow{ \bf{Volume \: of \: the \: wall = length \times breadth \times height}}}[/tex]

[tex]{\qquad \dashrightarrow{ \sf{Volume \: of \: the \: wall = 1000 \times 24 \times 400 \: {cm}^{3} }}}[/tex]

Now, each brick is a cuboid with Length = 24 cm, Breadth = 12 cm and height = 8 cm.

So,

[tex]{\qquad \dashrightarrow{ \bf{Volume \: of \: each \: brick = length \times breadth \times height}}}[/tex]

[tex]{\qquad \dashrightarrow{ \sf{Volume \: of \: each \: brick = 24 \times 12 \times 8 \: {cm}^{3} }}}[/tex]

So,

[tex]{\qquad \dashrightarrow{ \bf{Volume \: of \: bricks \: required = \dfrac{volume \: of \: the \: wall}{volume \: of \: each \: brick} }}}[/tex]

[tex]{\qquad \dashrightarrow{ \sf{Volume \: of \: bricks \: required = \dfrac{1000 \times 24 \times 400}{24 \times 13 \times 8} }}}[/tex]

[tex]{\qquad \dashrightarrow{ \sf{Volume \: of \: bricks \: required = \bf \: 4166.6} }}[/tex]

Therefore,