Respuesta :

4.58 is the pH of a buffer that contains 0.15 M [tex]CH_3COOH[/tex] and 0.10 M [tex]NaCH_3COO[/tex].

What is pH?

Potential of hydrogen; a measure of the acidity or alkalinity of a solution equal to the common logarithm of the reciprocal of the concentration of hydrogen ions in moles per cubic decimetre of solution.

Given data:

Ka = 1.8 X 10⁻⁵.

pKa = -logKa.

pKa = -log(1.8 X 10⁻⁵) = 4.75.

Henderson–Hasselbalch equation:

pH = pKa + log([tex]\frac{CH_3COOH}{NaCH_3COO}[/tex]).

pH = 4.75 + log(0.15 M /0.10 M).

pH = 4.75 - 0.17

pH = 4.58.

Hence, 4.58 is the pH of a buffer that contains 0.15 M [tex]CH_3COOH[/tex] and 0.10 M [tex]NaCH_3COO[/tex].

Learn more about the pH here:

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