The formulae of the metal according to the law of multiple proportions are XCl₂ and XCl₃, and X is Fe so FeCl₂ and FeCl₃
We have the two chlorides that are XyClw and XyClz. We have to show that the ratios w to z are in small whole numbers.
Compound A = 12.7 g X and 7.1 g Cl, then X must be 5.56 g
Compound B = 16.3 g X and 10.7 g Cl, then X must be 5.56 g.
7.1 x (12.7/16.3) = 5.53 g Cl for each gram of X
10.7 x (12/7/16.3) = 8.34 g Cl for each gram of X. Then what is the ratio of the two Cl numbers: Now, divide both numbers by the smaller one. That is
5.53/5.53 = 1.00
8.34/5.53 = 1.508.
Rounding off 1.508 to 1.50, then you can see that 1.0 to 1.5 is actually 2 to 3 and those are small whole numbers. Within experimental error, the law of multiple proportions is proved to be true.
The compounds must be XCl₂ and XCl₃, and X is Fe so FeCl₂ and FeCl₃ are the compounds.
To learn more about the law of multiple proportions, visit: https://brainly.com/question/28458716
#SPJ9
