At one university, the mean distance commuted to campus by students is 18.0 miles, with a standard deviation of 5.1 miles. suppose that the commute distances are normally distributed. complete the following statements.

Respuesta :

Approximately 99.75% of the students have commute distances between 2.7 miles and 33.3 miles.

How to calculate the confidence interval?

We are given;

Mean Distance; x' = 18 miles

Standard deviation; σ = 5.1 miles

Thus;

A) 2.7 = 18 - a(5.1)

where;

a is number of standard deviations away from the mean. Thus;

a = (18 - 2.7)/5.1

a = 3

3 standard deviations from the mean denotes that 99.7% of the data occurs within three standard deviations of the mean within a normal distribution.

B) At 95%, we have the data to be 2 standard deviations from the mean. Thus;

CI = 18 ± 2(5.1)

CI = (18 - 10.2) OR (18 + 10.2)

CI = (7.8, 28.2)

The statements to be completed are;

(a) Approximately ______ of the students have commute distances between 2.7 miles and 33.3 miles.

(b) Approximately 95% of the students have commute distances between _____ miles and ______ miles?

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