Answer:
[tex](-1.5,-2.25)[/tex]
Step-by-step explanation:
The first function is [tex]x^2-2x+y-3=0[/tex].
We make y the subject of this function to obtain,
[tex]y=3+2x-x^2[/tex].
This is graph will open downwards because [tex]a=-1\:<\:0[/tex].
At y-intercept of this graph, [tex]x=0[/tex].
[tex]\Rightarrow y=3+2(0)-(0)^2[/tex]
[tex]\Rightarrow y=3[/tex]
The y-intercept is [tex](0,3)[/tex].
At x-intercept [tex]y=0[/tex].
[tex]0=3+2x-x^2[/tex]
[tex]0=(x+1)(x-3)[/tex]
[tex]\Rightarrow x=-1,x=3[/tex].
The x-intercepts are,
[tex](-1,0),(3,0)[/tex]
Also the vertex form of the function is,
[tex]y=-(x-1)^2+4[/tex].
Therefore the vertex of the parabola is [tex](1,4)[/tex].
We plot all the points obtained and draw a smooth curve to obtain the curve as show in the diagram.
The second function is
[tex]x^2+y=0[/tex]
[tex]\Rightarrow y=-x^2[/tex]
This is the graph of the basic quadratic function [tex]y=x^2[/tex] that has been turned upside down.
This graph also has the vertex,y-intercept and x-intercept all at [tex](0,0)[/tex].
We now graph this too on the same graph sheet as the first one to obtain the blue graph as shown in the diagram.
These two graphs intersect at the point, [tex](-1.5,-2.25)[/tex].
Therefore the correct answer is B
Answer:
B. (-1.5, -2.25) EDG 2021
Step-by-step explanation:
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