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Exercises
Question-5 (doable)
A magnified, inverted image is located a distance of 38.0 cm from a converging lens with a focal
length of 10.0 cm. Determine the object distance and tell whether the image is real or virtual
[ 13.6 cm )

Respuesta :

[tex]\\ \rm\Rrightarrow \dfrac{1}{u}+\dfrac{1}{v}=\dfrac{1}{f}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{1}{u}=\dfrac{1}{-10}+\dfrac{1}{38}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{1}{u}=\dfrac{-19+5}{190}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{1}{u}=\dfrac{-14}{190}[/tex]

[tex]\\ \rm\Rrightarrow u=\dfrac{190}{-14}[/tex]

[tex]\\ \rm\Rrightarrow u=13.6cm[/tex]

Real

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