The height of the cliff will be 25.05 m. The height of the cliff is obtained by the Newton equation of motion.
The vertical distance between the object's top and bottom is defined as height. It is measured in centimeters, inches, meters, and other units.
The given data in the problem is;
Mass of diver(m)=90 kilogram
Time period(t)=2.26 sec
Initial velocity (u)=0 m/sec
The height attained by the cliff is;
[tex]\rm H = ut + \frac{1}{2}gt^2 \\\\ H=\frac{1}{2}gt^2\\\\ H= \frac{1}{2}(9.81)(2.26)^2\\\\ H= \frac{1}{2} \times 9.81 \times 5.1076 \\\\ H=25.05 \ m[/tex]
Hence, the height of the cliff will be 25.05 m.
To learn more about the height, refer to the link;
https://brainly.com/question/10726356
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