Using the Central Limit Theorem, it is found that the standard deviation for the sampling distribution of the sample proportions is of 0.062.
It states that for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1 - p)}{n}}[/tex], as long as [tex]np \geq 10[/tex] and [tex]n(1 - p) \geq 10[/tex].
In this problem:
Hence, the standard deviation is given by:
[tex]s = \sqrt{\frac{0.26(0.74)}{50}} = 0.062[/tex]
More can be learned about the Central Limit Theorem at https://brainly.com/question/24663213