The current moving through the traditional incandescent light bulb in the examined flashlight is 1.67A.
Electric power is simply the rate at which electrical energy is transferred by an electric circuit per unit time. It is equal to the voltage difference across the element multiplied by the current.
It can be expressed as;
P = V × I
Given the data in the question;
To determine the current moving through the bulb, we substitute our given values into the expression above.
P = V × I
60W = 36V × I
I = 60W / 36V
I = 1.67A
Therefore, the current moving through the light bulb is 1.67A.
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