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If your sample of vinegar is approximately 4.76% (w/w), what volume should you use so that approximately 40 mL of 0.1 M NaOH is required to neutralize your sample of vinegar

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mickymike92

Based on the concentrations given, the volume of vinegar required is 5.04 mL.

What is the concentration of the vinegar solution?

The concentration of a solution is the amount of solute in a given volume of solution.

Concentration can be expressed as:

  • molar concentration
  • percentage concentration

The concentration of the vinegar solution is 4.76% (w/w). This means that 4.76 g of vinegar is present in 100 g of solution.

Mass of vinegar = 4.76 g

molar mass if vinegar = 60 g/mol

moles of vinegar = 4.76/60 = 0.0793 moles

volume of solution/water = 100 mL or 0.1 L

Molarity of vinegar = 0.0793/0.1 = 0.793 M

1 mole of vinegar reacts with 1 mole of NaOH

let the volume of vinegar required be V

0.793 M × V = 40 × 0.1

V = 4/0.793

V = 5.04 mL

Therefore, the volume of vinegar require is 5.04 mL.

Learn more about molarity at: https://brainly.com/question/26528084

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