Respuesta :

The line that is perpendicular to [tex]y = \dfrac{4}{5}x+23[/tex] and passes through (-40,20) is [tex]y = \dfrac{-5}{4}x-30[/tex].

We have to determine, which equation represents the line that is perpendicular to y = 4/5x+23 and passes through (-40,20).

According to the question,

Equation of line; [tex]y = \dfrac{4}{5}x+23[/tex]

To determine the equation perpendicular line passes through the given points determined in the following steps given below.

  • Step1; The slope of the given line is,

                   [tex]m = \dfrac{4}{5}[/tex]

  • Step2; The negative slope of that slope is,

                    [tex]m = \dfrac{-5}{4}[/tex]

  • Step3; The perpendicular line passes through the points (-40, 20),

                    [tex]y = mx + b\\\\20 = \dfrac{-5}{4} \times -40 + b\\\\20 = -5 \times -10 +b \\\\20 = 50 + b \\\\b = 20-50\\\\b = -30[/tex]

  • Step 4; The required line is,

                     [tex]y = mx + b\\\\y = \dfrac{-5}{4}x-30[/tex]

Hence, The line that is perpendicular to [tex]y = \dfrac{4}{5}x+23[/tex] and passes through (-40,20) is [tex]y = \dfrac{-5}{4}x-30[/tex].

To know more about the Straight line click the link given below.

https://brainly.com/question/1249

ANSWER:}---> y=-5/4x-30