Respuesta :

Annder

Explanation:

LiCl2 3 M =

in sol. 1 L there is LiCl2 3 mol

if sol. 0.5 L there is LiCl2 0.5×3 = 1.5 mol

LiCl2 = 6.9 + 35.5(2)

= 6.9 + 71

= 77.9 g

TheDoctorOfStone

Answer:

63.52g of LiCl are in a 3.0 molarity solution of 0.5L

Explanation:

Moles = Molarity x Volume

Molarity = 3.0 mol/L

Volume = 0.5L

Moles = (3.0) x (0.5)

Moles = 1.5

In order to find the grams dissolved in the solution, we must first find the molar mass of Lithium Chloride (LiCl).

Molar mass of LiCl = (6.9) + (35.45) = 42.35g/mol

Now we multiply the moles by the molar mass of LiCl to get the grams of LiCL dissolved in the solution.  

1.5 * 42.35 = 63.52g of LiCl

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