Respuesta :
The given distances and time give the speed of each elevator. The
distances traveled in 12 and 35 seconds can be found from the speed.
Correct responses:
- The elevator that travels approximately 280 feet in 12 seconds is the elevator in the Empire State Building.
- The elevator that travels about 935 feet in 35 seconds is the elevator in Willis Tower.
Methods used to find the specified elevator
The possible given data based on a similar question posted online is presented as follows;
[tex]\begin{tabular}{|l|c|c|c|} \underline{Building} & \underline{Approximate Distance (feet)}& \underline{Time (seconds)}& \underline{Speed (ft./s)}\\Empire State Building&233&10&23.3\\John Hancock Center&150&5&30\\One World Trade Center&666&20&33.3\\Space Needle&368&25&14.72\\Willis Tower&401&15&26.7\overline{3}\end{array}\right] [/tex]
The speed of each elevator is given by the following formula;
[tex]Speed = \mathbf{\dfrac{Distance}{Time} }[/tex]
The speed of the elevators are therefore;
[tex]Elevator \ speed \ in \ \mathbf{Empire \ State \ Building} = \dfrac{233 \, ft.}{10 \, s} = 23.3 \, ft./s.[/tex]
[tex]Elevator \ speed \ in \ \mathbf{John \ Hancock \ Center} = \dfrac{150 \, ft.}{5 \, s.} = 30 \, ft./s[/tex]
[tex]Elevator \ speed \ in \ \mathbf{One \ World \ Trade \ Center} = \dfrac{666 \, ft.}{20 \, s.} = 33.3 \, ft./s.[/tex]
[tex]Elevator \ speed \ in \ \mathbf{Space \ Needle} = \dfrac{368 \, ft.}{25 \, s} = 14.72 \, ft./s.[/tex]
[tex]Elevator \ speed \ in \ \mathbf{Willis \ Tower} = \dfrac{401 \, ft.}{15 \, s.} = 26.7\overline{3} \, ft./s. \approx 26.7 \, ft./s.[/tex]
Distance travelled in 12 seconds is therefore;
Distance, d, traveled by the elevator in Empire state building
d = 23.3 ft./s × 12 s. = 279.6 ft ≈ 280 feet in 12 seconds
Therefore;
- The elevator that travels approximately 280 feet in 12 seconds is the elevator in the Empire State Building.
Distance traveled in 35 seconds.
The distance traveled by the elevator in Willis Tower in 35 seconds is given as follows;
- [tex]Distance = 26.7\, ft./s \times 35 \, s = 934.5 \, ft. \approx 935 \, ft.[/tex]
Therefore;
- The elevator that travels about 935 feet in 35 seconds is the elevator in Willis Tower.
Learn more about the calculation of speed here:
https://brainly.com/question/2142871
