Respuesta :
Answer:
Option D)
Step-by-step explanation:
If the graph of the function [tex]f(x)=g(x+h) +b[/tex] represents the transformations made to the graph of [tex]y= g(x)[/tex] then, by definition:
If [tex]b> 0[/tex] the graph moves vertically b units up
If [tex]b <0[/tex] the graph moves vertically b units down
If [tex]h>0[/tex] the graph moves horizontally h units to the left
If [tex]h> 1[/tex] the graph moves horizontally h units to the rigth
In this problem we have the function [tex]f(x)=2^x+k[/tex] and our parent function is [tex]g(x) = 2^x[/tex]
therefore it is true that [tex]b =k<0[/tex] and [tex]h= 0[/tex]
Then "The graph of f(x) is shifted k units below the graph of g(x)".
The answer is Option D)
_________________________________________________
Note:
If the function are:
[tex]g(x) = 2^x\\\\f(x) = 2^{x+k}[/tex]
Then [tex]k = h[/tex] and [tex]h<0[/tex]. This means that the function f(x) shifts k units to the right of the function g(x)
And the answer would be the option B)
Answer:
B) The graph of f(x) is shifted k units to the right of the graph of g(x).
Step-by-step explanation:
We given the functions [tex]g(x) = 2^x[/tex] and [tex]f(x)=2^{x+k}[/tex] where [tex]k <0[/tex].
We know that horizontal depends on the value of x and are when
[tex]g(x)=f(x+h)[/tex] when graph is shifted to left; and
[tex]g(x)=f(x-h)[/tex] when graph is shifted to right.
Given the above functions, when k is considered positive then f(x) becomes [tex]f(x)=2^{x+k}=g(x-k)[/tex].
Therefore, the graph of f(x) is shifted k units to the right of the graph of g(x).