The statement which correctly describes the number of possible positive zeros and the number of possible negative zeros is
[tex]f(x)=x^4+2x^3-11x^2-5x-6[/tex]
there is only one sign change
So, there is a maximum of 1 positive zero
[tex]f(-x) = (-x)^4 + 2(-x)^3 - 11(-x)^2 - 5(-x) - 6\\\\f(-x) = x^6 - 2x^3 - 11x^2 + 5x - 6[/tex]
Sign changes 3 times
So, number of negative zeros is either 3 or 1
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