contestada

Find the area of a triangle whose base is 2√3 in. and height is 3√3 in.

6√3 in.²
9 in.²
18 in.²

Respuesta :

ferretgirl02
area of a triangle = (b x h) /2
(2√3 × 3√3 )/2=
(2×3√3×3)/2 =
(6√9)/2 =
(6×3)/2 =
18/2 =
9 in²
Hope this helps

Answer:

B. 9 inch²

Step-by-step explanation:

We are given that,

Base of the triangle = [tex]2\sqrt{3}[/tex] inches

Height of the triangle = [tex]3\sqrt{3}[/tex] inches

Now, Area of the triangle = [tex]\frac{1}{2}(Base\times Height)[/tex]

i.e. Area of the triangle = [tex]\frac{1}{2}(2\sqrt{3}\times 3\sqrt{3})[/tex]

i.e. Area of the triangle = [tex]\frac{1}{2}(6\times 3)[/tex]

i.e. Area of the triangle = [tex]\frac{18}{2}[/tex]

i.e. Area of the triangle = 9 inch²

Thus, the area of the triangle is 9 inch².

So, option B is correct.

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