Answer:
a).[tex]x=47.8m[/tex]
b).[tex]x=246.12m[/tex]
Explanation:
a).
[tex]x=v_{ox}*t[/tex]
[tex]y=y_i+v_{oy}+\frac{1}{2}*a_y*t^2[/tex]
[tex]v_{ox}=670 m/s[/tex]
[tex]y=\frac{1}{2}*a_y*t^2[/tex]
[tex]y=0.025m[/tex]
[tex]t=\sqrt{\frac{2*-y}{-g}}=\sqrt{\frac{-2*0.025m}{-9.8m/s^2} }[/tex]
[tex]t=0.0714s[/tex]
[tex]x=v_{ox}*0.0714s[/tex]
[tex]x=670*0.0714=47.8m[/tex]
b).
Assume a normal person fired the rifle with a high of 1.8m so:
[tex]x=v_{ox}*\sqrt{\frac{2*h}{g}}[/tex]
[tex]x=670(m/s)*\sqrt{\frac{2*1.8m}{9.8m/s^2}}[/tex]
[tex]x=246.12m[/tex]
