Respuesta :
- a 10 m long wire of mass of 123g is stretched under a tension of 255N. a generated atone end and 20ms later a second pulse is generated at the opposite end where n = mass of the wire / length = 123 x 10^-3 /10 = 1.23 kg/m v = √(255/1.23) = 14.4 m/s
Answer:
10 m/s
Explanation:
I took the test, had the same question. Also it's ez math l0l
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